9a^2+1=442

Solution for 9a^2+1=442 equation:

9a^2+1=442

We move all terms to the left:

9a^2+1-(442)=0

We add all the numbers together, and all the variables

9a^2-441=0

a = 9; b = 0; c = -441;
Δ = b2-4ac
Δ = 02-4·9·(-441)
Δ = 15876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{15876}=126$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-126}{2*9}=\frac{-126}{18}
=-7
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+126}{2*9}=\frac{126}{18}
=7
$